# author : 202213216李豆豆
# 1.计算下列各计算式的值
import math

# ①√π2+3
a1 = math.sqrt(2 * math.pi) + 3
print(f"①√π2+3 = {a1}")
# ② In (2π√13+ e )
a2 = math.log((math.sqrt(13) + 2 * math.pi) + math.e)
print(f"② In (2π√13+ e ) = {a2}")
# ③ (tan^-1)* log3( π +1)
a3 = math.atan(math.log((math.pi + 1), 3))  # 这里求的是arctan(log以3为底pi+1的对数)
print(f"③ (tan^-1)* log3( π +1) = {a3}")
